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=0.3G-0.2G^2
We move all terms to the left:
-(0.3G-0.2G^2)=0
We get rid of parentheses
0.2G^2-0.3G=0
a = 0.2; b = -0.3; c = 0;
Δ = b2-4ac
Δ = -0.32-4·0.2·0
Δ = 0.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.3)-\sqrt{0.09}}{2*0.2}=\frac{0.3-\sqrt{0.09}}{0.4} $$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.3)+\sqrt{0.09}}{2*0.2}=\frac{0.3+\sqrt{0.09}}{0.4} $
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